A particle moves in a circular path of radius 5 cm in a plane perpendicular to the principla axis of a xonvex mirror with radius of curvature 20cm. The object is 15cm in front of the mirror. Calculate the radius of the circular path of the image.

Explanation

`u=-15cm, f=(+20)/(2)=10cm`
`(1)/(-15)+(1)/(v)=(1)/(10)`
`(1)/(v)=(1)/(10)+(1)/(15)rArrv=6cm`
`m=-(v)/(u)=(h_(2))/(h_(1))`
`(-6)/(-15)=(h_(2))/(5)rArr h_(2)=2cm`
So, radius of circulart path of the image is 2 cm.