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A spherical surface of radius R ssparate...

A spherical surface of radius R ssparates two media of refractive indices `mu_(1)` and `mu_(1)` as shown in figure., Where should an object be placed in medium 1 so that a real image is formed in medium 2 at the same distance?

Text Solution

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Let x be the distance of the object from the pole in medium 1.
Here we have , `u=-x, v=+x and R=+R`
Using the equation, we get `(mu_(2))/(+x)-(mu_(1))/(-x) =(mu_(2)-mu_(1))/(+R)`
or `x=((mu_(2)+mu_(1))/(mu_(2)-mu_(1)))R`
Note that the real image is formed only when `mu_(2) gt mu_(1)` .
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Knowledge Check

  • A curved surface of radius R separates two medium of refractive indices mu_(1) "and" mu_(2) as shown in figures A and B . Choose the correct statement(s) related to the real image formed by the object O placed at a distance x, as shown in figure A.

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    Real image is formed only when x>R
    C
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    D
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  • A curved surface of radius R separates two medium of refractive indices mu_(1) and mu_(2) as shown in figures A and B Choose the correct statement(s) related to the real image formed by the object O placed at a distance x, as shown in figure A

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    Virtual image is formed for any position of O if `mu_(2) lt mu_(1)`
    B
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