A converging bundle of rays travel from water (refractive index `4//3` ) to glass (refractive index 1.5) through a convex interface of radius 16cm. In the absence of the interface, The rays would have converged to a point 32 cm from the pole of the interface. Where will the rays actually meet after refraction?

Explanation

We now have refraction at a single curved surface. The coordinate system for this problem is shown in figure.
Refraction: Ray from water to glass
`mu_(1)=(4)/(3), mu_(2)=1.5`
`u=+32cm, R=+16cm`
Substituting in the equation
`mu_(2)/(v)-(mu_(1))/(u)=(mu_(2)-mu_(1))/(R)`
we get `v=+(144//5) cm`
I.e., the object appears to be `144//5` cm to the right of interface.