Home
Class 12
PHYSICS
A biconvex lens has radii of curvature 2...

A biconvex lens has radii of curvature 20 cm and 40cm. The refractive index of the material of the lens is 1.5. An object is placed 40cm in front of the lens. Calculate the psition of the image.

Text Solution

AI Generated Solution

To solve the problem step by step, we will use the lens maker's formula and the lens formula to find the position of the image formed by the biconvex lens. ### Step 1: Determine the focal length of the lens using the lens maker's formula. The lens maker's formula is given by: \[ \frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) ...
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS|Exercise Exercise1.7|21 Videos
  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS|Exercise Subjective|26 Videos
  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS|Exercise Exercise1.5|22 Videos
  • FRICTION

    CENGAGE PHYSICS|Exercise QUESTION BANK|1 Videos
  • GRAVITATION

    CENGAGE PHYSICS|Exercise Question Bank|39 Videos

Similar Questions

Explore conceptually related problems

A bicovex lens has radii of cuvature 20 cm each. If the refractive index of the material of the lens is 1.5, what is its focal length?

A plano-convex lens is silvered on its plane side. The radius of curvature of the other face is 12cm and the refractive index of the material of the lens is 1.5. An object is placed 24 cm in front of the silvered lens. Where will the image be formed?

A concave lens has radioi of curvatures of 20 cm and 30 cm respectively. If the refrative index of the material of lens is 1.6 it focal length is given by

A double convex lens has faces of radii of curvature 30 cm each. The refractive index of the material of the lens is 1.5. What is the focal length of this lens when immersed is carbondisulphide of refractive index 1.6 ?

A converging bundle of rays is intercepted by a biconcave lens. The radii of curvature of both surfaces are 20cm and the refractive index of the material of the lens is 1.5. If the rays originially converged to a point 10cm in front of the lens, where will they now converge after passing through the lens?

Power of biconvex lens is 10 diopters and radius of curvature of each surface is 10cm.Then refractive index of material of lens is

A glass slab of thickness 2cm and refractive index 2 is placed in contact with a biconvex lens of focal length 20cm. The refractive index of the material of the lens 1.5 . The far side of the lens is silvered. Where should an object be placed in front of the slab so that it images on to itself?