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Two identical glass (mu(g)=3//2) equicon...

Two identical glass `(mu_(g)=3//2)` equiconvex lenses of focal length `f` are kept ini contact. The space between the two lenses is filled with water `(mu_(w)=4//3)`. The focal length of the combination is

A

f

B

`(f)/(2)`

C

`(4f)/(3)`

D

`(3f)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
d.

Let R be the radius of curvature of each surface. Then
`(1)/(f)=(1.5-1)((1)/(R)+(1)/(R))`
For the water lens,
`(1)/(f^('))=((4)/(3)-1)(-(1)/(R)+(1)/(R))=(1)/(3)(-(2)/(f)),`
`(1)/(f^('))=-(2)/(3f)`
Now, using `(1)/(F)-(1)/(f_(1))+(1)/(f_(2))+(1)/(f_(3))`, we have
`(1)/(F)-(1)/(f)+(1)/(f)+(1)/(f^('))=(2)/(f)-(2)/(3f)=(4)/(3f)`
`rArr F=(3f)/(4)`
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