Find the distance of object placed in the slab of refractive index `mu` from point P of the curved surface of radius R so that image is formed at infinity:

Options

A. `((mu-1)R)/(mu)`
B. `(muR)/((mu-1))`
C. `(R)/((mu-1))`
D. `((mu-1)R)/(2mu)`

Answer

b.

Explanation

`(mu_(2))/(v)-(mu_(1))/(u)=(mu_(2)-mu_(1))/(R)`
`mu_(2)=1,mu_(1)=mu,u=-v,R=-R`
`(1)/(v)-(u)/((-u))=(1-u)/((-R))`
`(1)/(v)=(u(mu-1)-muR)/(uR)`
`v=(uR)/(u(mu-1))`
For `v=oo,u(mu-1)-muR=0`
`u=(muR)/((mu-1))`