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STATEMENT-1 The focal length of a lens d...

STATEMENT-`1` The focal length of a lens does not depend on the medium in which it is submerged.
`STATEMENT 2 (1)/(f)=(mu_(2)-mu_(1))/(mu_(1))((1)/(R_(1))-(1)/(R_(2)))`

A

Statement is True, Statement II is True, Statement II is correct explanation for Statement I

B

Statement I is True, Statement II is True, Statement II is NOT a correct explanation for Statement I.

C

Statement I is True, Statement II is False.

D

Statement I is False, Statement II is True.

Text Solution

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The correct Answer is:
d.
As can be seen from the expression of f, it depends upon the refractive index of the medium in which the lens is submerged.
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STATEMENT- 1 The focla lengh of a lens does not depend on the medium in which it is submerged. STATEMENT 2 (1)/(f)=(mu_(2)-mu_(1))/(mu_(1))((1)/(R_(1))-(1)/(R_(2)))

Assertion : A double convex lens (mu=1.5) has focal length 10 cm . When the lens is immersed in water (mu=4//3) its focal length becomes 40 cm . Reason : (1)/(f)=(mu_(1)-mu_(m))/(mu_(m))((1)/(R_(1))-(1)/(R_(2)))

STATEMENT- 1 Power of a lens depends on nature of material of lens, medium in which it is placed and radii of curvature of its surface. STATEMENT 2 it follows the relation p=(1)/(f)=((mu_(2))/(mu_(1))-1)[(1)/(R_(1))-(1)/(R_(2))]

STATEMENT- 1 Air bubble in glass medium behaves as concave lens. STATEMENT 2 Lens formula is (1)/(f)=((mu_("lens"))/(mu_("med"))-1) [(1)/(R_(1))-(1)/(R_(2))]

Statement-1 : Focal length of an equiconvex lens of mu = 3//2 is equal to radius of curvature of each surface. Statement-2 : it follows from (1)/(f) = (mu - 1)((1)/(R_(1)) - (1)/(R_(2)))

The focal length of equiconvex lens of retractive index, mu=1.5 and radius of curvature, R is

Statement-1 : A glass convex lens (refractive index, mu_(1)=1.5 ), when immersed in a liquid of refractive index mu_(2)=2 , functions as a diverging lens. Statement-2 : The focal length of a lens is given by (1)/(f)=(mu-1)((1)/(R_(1))-(1)/(R_(2))) , where mu is the relative refractive index of the material of the lens with respect to the surrounding medium.

A point source of light is placed inside water and a thin converging lens ofrefractive index mu_(2) is placed just outside the plane surface of water. The image of the source is formed at a distance x from the surface of water. If the lens is now placed just inside water and the image is now formed at a distances' from the surface of water, show that (1)/(x) -(1)/(x_(1)) = (mu_(1)-1)/(mu_(2)-1) xx (1)/(f) , Where f is the focal length of the lens and mu_(1) is the refractive index of water.

STATEMENT- 1 A convex lens of focal length (f=1.5) behaves as a diverging lens when immersed in carbon di-sulphide of higher refractive index (f=1.65) STATEMENT 2 the focal length of lens does not depend on the colour of light used.

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