What is the velocity (in cm`s^(-1)` ) of image in situation shown in figure, `(O=` object, `f=` focal length ). Object moves with velocity `10cm//s` and mirror moves with velocityy `2cms^(-1)` as shown.

Answer

0

Explanation

`(1)/(y)+(1)/(-x_(1))=(1)/(10)` (i)
`(1)/(y)-(1)/(10)=(1)/(10)rArry=5cm`
`(dx)/(dt)=10cms^(-1), (d(x+x_(1)))/(dt)=2cms^(-1)`
`(dx_(1))/(dt)=-8cms^(-1)`
`(dy)/(dt)=v_(i)=2`
From (i) `:(dy)/(dt)=((y)/(x_(2)))^(2)(dx_(1))/(dt)`
`rArrv_(i)-2=((5)/(10))^(2)(-8)rArr v_(i)=0`