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If epsilon(0) and mu(0) are, respectivel...

If `epsilon_(0)` and `mu_(0)` are, respectively, the electric permittivity and magnetic permeability of free space, `epsilon` and `mu` the corresponding quantities in a medium, the index of refraction of the medium in terms of the above parameters is `"________________"`.

Text Solution

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We known that the velocity of light in vacuum,
`c=(1)/(sqrt(mu_(0)epsilon_(0)))`
Also, the velocity of light in a medium, `v=(1)/(sqrt(muepsilon))`
`:. n=("Velocity of light in medium")/("Velocityof light in nvacuum")`
`=(v)/(c)=(1//sqrt(mu_(0)epsilon_(0)))/(1//sqrt(muepsilon))=(sqrt(muepsilon))/(sqrt(mu_(0)epsilon))`
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