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A ray of light travelling in the direction `1/2 (hati+sqrt(3)hatj)` is incident on a plane mirror. After reflectiion, it travels along the direction `1/2(hati -sqrt(3)hatj)`. The angle of incidence is

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`75^(@)`

Text Solution

Verified by Experts

The correct Answer is:
a.

Let anglel between the directions of incident ray and reflected ray be `theta`
`costheta=(1)/(2)(hat(i)+sqrt(3)hat(j))*(1)/(2)(hat(i)-sqrt(3)hat(j))`
`=-(1)/(2)`
`theta=120^(@)`
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