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Water (with refractive index =4//3) in a...

Water (with refractive index `=4//3`) in a tank is 18cm deep. Oil of refractive index `7//4` lies on water making a convex surface of radius of curvature `R=6cm` as shown. Consider oil to act as a thin lens. An object S is placed 24cm above water surface. The location of its image is at 'x' cm above the bottom of the tank. Then x is

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The correct Answer is:
2
`(mu_(2))/(v)-(mu_(1))/(u)=(mu_(2)-mu_(1))/(R)`
`(7)/(4v)-(1)/(-24)=((7)/(4)-1)/(6)`
`(7)/(4v)=(3)/(24)-(1)/(24)=(2)/(24)=(1)/(12)`
`(7xx2)/(4)=V=21cm`
`(21)/(OS^(''))=(7//4)/(4//3)rArr OS^('')=16`
`:.BS^('')=2cm`
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