In Young's experiment, light of wavelength 600 nm falls on the double slits separated by 0.1 mm. What is the highest order of maximum intensity in the interference pattern obtained on a screen kept 3 m from the slits? How does the highest order change if the distance of screen from the slits is changed?

Explanation

As we know, `n_(max) = (d)/(lambda)`
Given `d = 0.1 mm = 0.1 xx 10^(-3) m`
and `lambda = 600 nm = 600 xx 10^(-9) m.`
`:. n_(max) = (0.1 xx 10^(-3))/(600 xx 10^(-9)) = 166.67 implies n_max =166`
Obviously, `n_max = d//lambda` does not depend on the distance of screen form the slits.
Hence, it remains 166 if the distance between the slits and the screen is changed.