The intensity of the light coming from one of the slits in a Young's double slit experiment is double the intensity from the other slit. Find the ratio of the maximum intensity to the minimum intensity in the interference fringe pattern observed.

Explanation

`(I_(max))/(I_(min)) = [(sqrt I_(1))/(sqrt I_(1)) + (sqrt I_(2))/(sqrt I_(2))]^(2)`
As `I_(1) = 2 I_(2)`
`implies (I_(max))/(I_(min)) = [(sqrt 2 + 1)/(sqrt 2 - 1)]^(2) = 34`.