Slit 1 of Young's double-slit experiment is wider then slit 2, so that the light from slits are given as `A_(2) = A_(3) A_(0) sin (omega + (pi)/(3))`, The resultant amplitude and intensity, at a point where the path difference between them is zero, are A and I, respectively. Then

Options

A. `A = sqrt (13) A_(0)`
B. `A = 4 A_(0)`
C. `I prop 16 A_(0)^(2)`
D. `I prop 13 A_(0)^(2)`

Answer

a.,d

Explanation

If the amplitudes due to two individual sources at point P and `A_(0)` and `3 A_(0)`, then the resultant amplitude at P will be
`A = sqrt(A_(0)^(2) + (3 a_(0))^(2) + 2(A_(0))(3A_(0)) cos pi // 3)`
`= A_(0)`
Resultant intensity, `I prop 13 A_(0)^(2)`