A narrow tube is bent in the form of a circle of radius R, as shown in figure. Two small holes S and D are made in the tube at the position at right angle to each other. A source placed at S generates a wave of intensity `I_(0)` which two parts: one part travels along the longer path, while the other travels along the shorter path. Both the waves meet at point D where a detector is placed.

The maximum intensity produced at D is given by

Options

A. `4 I_(0)`
B. `2 I_(0)`
C. `I_(0)`
D. `3 I_(0)`

Answer

b

Explanation

Maximum intensity, `I_(max) = (sqrt I_(1) + sqrt I_(2))^(2)`
Here, `I_(1) = I_(2) = (I_(0))/(2)` (given)
`:. I_(max) = (sqrt((I_(0))/(2)) + sqrt((I_(0))/(2)))^(2) = 2 I_(0)`