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An interference is observed due to two c...

An interference is observed due to two coherent sources `S_(1)` placed at origin and `S_(2)` placed at (0, 3l, 0). Here, `lambda` is the wavelength of the sources. Both sources are having equal intensity `I_(0)`. A detector D is moved along the positive x-axix.

Total number of black points observed by the observer on positive x-axis is

A

two

B

four

C

three

D

five

Text Solution

Verified by Experts

The correct Answer is:
b

At ` x = 0`, path difference is `3 lambda`. Hence,third-order maximum will be obtained. At `x = oo`, path difference is zero. Hence, zero-order maxima is obtained. In between, first - and second-order maxima will be obtained. First order maxima:
`S_(2) P - S_(1) P = lambda` or `sqrt(x^(2) + 9lambda^(2)) - x = lambda`
or `sqrt(x^(2) + 9 lambda^(2)) = x + lambda`
Squaring this, we get `x^(2) + 9 lambda^(2) = x^(2) + lambda^(2) + 2 x lambda`
Solving this, we get `x = 4 lambda`
Second-order maxima:
`S_(2) P - S_(1) P = 2 lambda` or `sqrt(x^(2) + 9 lambda^(2)) - x = 2 lambda`
or ` sqrt( x^(2) + 9 lambda^(2)) = (x + 2 lambda)`
Squaring both sides, we get
`x^(2) + 9 lambda^(2) = x^(2) + 4 lambda^(2) + 4 x lambda`
Solving this, we get `x = (5)/(4) lambda = 1.25 lambda`
Hence, the desired x-corrdinates are
`x = 1.25 lambda` and `x = 4 lambda`
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