The figure shows the interfernece pattern obtained in double slit experiment using light of wavelength 600 nm.
Q. Let `DeltaX_(A)` and `DeltaX_(C)` represent path differences between waves interering at 1 and 3 respectively then `(|DeltaX_(C)|-(|DeltaX_(A)|)` is equal to

Options

A. 0
B. 300mn
C. 600nm
D. 900nm

Answer

b

Explanation

`Delta X_(C) = lambda, Delta X_(A) = (lambda)/(2)`
`Delta X_(C) - Delta X_(A) = (lambda)/(2) = 3000` nm