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In the Young's double slit experiment, t...

In the Young's double slit experiment, the interference pattern is found to have as intensity ratio between the bright and dark fringes as 9. This implies that

A

the intensities at the screen due to the two slits are 5 units and 4 units, respectively

B

the intensities at the screen due to the two slits are 4 unit and 1 units, respectively

C

the amplitude ratio is 3

D

the amplitude ratio is 2

Text Solution

Verified by Experts

The correct Answer is:
b.,d
We know that
`(I_(max))/(I_(min)) = ((a + b)^(2))/((a - b)^(2))`
Where `I_(1) prop a^(2)` (a is amplitude of 1 wave) and `I_(2) prop b^(2)` (b is amplitude of 2 wave). Hence,
`(I_(max))/(I_(min)) = (9)/(1) implies (a + b)/(a - b) = (3)/(1) implies (a)/(b) = (1)/(2)`
`:. (I_(1)^(2))/(I_(2)^(2)) = (a^(2))/(b^(2)) = (1)/(4)`
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