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When a certain metallic surface is illum...

When a certain metallic surface is illuminated with monochromatic light of wavelength `lamda`, the stopping potential for photoelectric current is `3V_0` and when the same surface is illuminated with light of wavelength `2lamda`, the stopping potential is `V_0`. The threshold wavelength of this surface for photoelectrice effect is

A

`6lamda`

B

`(4lamda)/(3)`

C

`4lamda`

D

`8lamda`

Text Solution

Verified by Experts

The correct Answer is:
C
Using photoelectric equation,
`hv-hv_0=(1)/(2)mv^2=eV_s`
or `((hc)/(lamda)-(hc)/(lamda_0))=eV_s`
For the first case, `(hc)/(2lamda)-(hc)/(lamda_0)=e(3V_0)` ...(i)
For the second case, `(hc)/(2lamda)-(hc)/(lamda_0)=e(eV_0)`..(ii)
Solving `lamda_0=4lamda`
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  • When a certain metallic surface is illuminated with monochromatic light of wavelength lambda , the stopping potential for photo electric current is 6 v_(0) . When the same surface si illuminated with light of wavelength 2 lambda , the stopping potential is 2v_(0) . The threshold wavelength of this surface for photoelectric effect is -

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