In the intercept on the y-axis is equal to

Options

A. `+(W)/(e)`
B. `-(W)/(e)`
C. `-We`
D. `(e)/(W)`

Answer

B

Explanation

The maximum KE of the photoelectrons is given by
`((1)/(2)mv^(2))_(max)=hv-W`
Now, `v=c/(lamda)` and ` ((1)/(2)mv^(2))=eV`
`eV=(hc)/(lamda)-W` or `V=((hc)/(e))(1)/(lamda)-(W)/(e)`
Since V is represented along y-axis and `((1)/(lamda))` along x-axis, the above equation represents a straight line. Slope of straight line `=(hc)/(e)`
Intercept of straight line `=-((W)/(e))`