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Lights of two different frequencies whose photons have energies 1 and 2.5 eV, respectively, successively illuminate a metal whose work function is 0.5 eV. The ratio of the maximum speeds of the emitted electrons

A

`1:5`

B

`1:4`

C

`1:2`

D

`1:1`

Text Solution

Verified by Experts

The correct Answer is:
C

If E is the energy of incident photon and W the work function, then `E_W_0="available energy"`
`E-W_0=(1)/(2)mv^(2)`
or `v=sqrt((2(E-W_0))/(m))`
`(v_1)/(v_2)=sqrt((1-0.5)/(2.5-0.5))=sqrt((0.5)/(2))=(1)/(2)`
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