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Light from a hydrogen tube is incident o...

Light from a hydrogen tube is incident on the cathode of a photoelectric cell the work function of the cathode surface is `4.2 eV`. In order to reduce the photo - current to zero the voltage of the anode relative to the cathode must be made

A

`-4.2 V`

B

`-9.4 V`

C

`-17.8 V`

D

`+9.4 V`

Text Solution

Verified by Experts

The correct Answer is:
B
H discharge tube means max. `hupsilon=13.6eV`. Work function `=4.2 V`. So, `(13.6-4.2)V=9.4V`. So, required voltage is `-9.4V`.
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