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The work function of a metallic surface ...

The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength `2000A` falls on it. The potential difference applied to stop the fastest photoelectrons is

A

1.2 V

B

2.24 V

C

3.6 V

D

4.8 V

Text Solution

Verified by Experts

The correct Answer is:
A
`eV=hv-phi_0`
`=((12375)/(2000)-5.01)eV`
`V=(6.1875-5.01)V-1.18Vapprox1.2V`
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