A material particle with a rest mass `m_o` is moving with a velocity of light c. Then, the wavelength of the de Broglie wave associated with it is

Options

A. `((h)/(m_oc))`
B. zero
C. `infty`
D. `((m_oc)/(h))`

Answer

B

Explanation

We know that mass m in motion and the rest mass `m_0` is related through the equation
`m=(m_0)/(sqrt(1-(v^2)/(c^2)))`
As `v=c`,`m=(m_0)/(sqrt(1-1)=(m_0)/(0)=infty`
Therefore, de Broglie wavelength is
`lamda=(h)/(mv)=(h)/((infty)(c ))=0`