The ratio of moment of an electron and an `alpha`-particle which are accelerated from rest by a potential difference of `100V` is

Options

A. 1
B. `sqrt((2m_e)/(m_alpha))`
C. `sqrt((m_e)/(m_alpha))`
D. `sqrt((m_e)/(2m_alpha))`

Answer

D

Explanation

`lamda=(h)/(sqrt(meV)`
`p=sqrt(2meV)`
`(p_e)/(p_alpha)=sqrt((2m_eeV)/(2m_alpha(2e)V))`
`(p_e)/(p_alpha)=sqrt((m_e)/(2m_alpha))`