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The kinetic energy of an electron is E w...

The kinetic energy of an electron is E when the incident wavelength is `lamda` To increase ti KE of the electron to 2E, the incident wavelength must be

A

`2lamda`

B

`(lamda)/(2)`

C

`(hclamda)/(Elamda+hc)`

D

`(hclamda)/(Elamda+hc)`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=(hc)/(lamda)-phi_0`
`2E=(hc)/(lamda')-phi_0`
or solvi ng `lamda'=(hclamda)/(Elamda+hc)`
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