The de Broglie wavelength of neutrons in thermal equilibrium is (given `m_n=1.6xx10^(-27)`kg)`

Options

A. `(30.8)/(sqrtT)A`
B. `(3.08)/(sqrtT)A`
C. `(0.308)/(sqrtT)A`
D. `(0.0308)/(sqrtT)A`

Answer

A

Explanation

`lamda=(h)/(sqrt(2meT))`
`=(6.62xx10^(-34))/(sqrt(2xx1.67xx10^(-27)xx1.38xx10^(-23)T))m`
`=(6.62xx10^(-34))/(2.15xx10^(-25)sqrtT)m`
`(3.079)/(sqrtT)xx10^(-9)m=(30.79)/(sqrtT)Aapprox(30.8)/(sqrtT)A`