An electron is accelerated through a potential difference of V volt. It has a wavelength `lamda` associated must be accelerated so that its de Broglie wavelength is the same as the of a proton? Take mass of proton to be 1837 times larger than the mass of electron.

Options

A. V volt
B. 1837V volt
C. `(V)/(1837)` volt
D. `sqrt(1837) V` volt

Answer

C

Explanation

`lamda=(h)/(sqrt(2mqV))`
`mV="constant"`
`1837V'=1xxV` or `V^`=(V)/(1837)`volt