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Figure shows the plot of the stopping po...


Figure shows the plot of the stopping potential versus the frequency of the light used in an experiment on photoelectric effect. The ratio `(h)/(e)` is

A

`10^(-15)Vs^(-15)Vs`

B

`2xx10^(-15)Vs`

C

`3xx10^(-15)Vs`

D

`4.14xx10^(-15)Vs`

Text Solution

Verified by Experts

The correct Answer is:
D
`eV_S=hc-phi_0`
`V_S=(h)/(e)v-(phi_0)/(e)`
Now, `(h)/(e)="slope"=(1.656)/(4xx10^(14))`
`=0.414xx10^(-14)Vs`
`4.14xx10^(-15) Vs`
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