The potential difference applied to an X-ray tube is V The ratio of the de Broglie wavelength of electron to the minimum wavlength of X-ray is directrly proportional to

Options

A. V volt
B. `sqrtV`
C. `V^((3)/(2))`
D. `V((7)/(2))`

Answer

B

Explanation

`lamda=(h)/(sqrt(2meV))`
`(hc)/(lamda_(min))=eV`
`lamdaxx(hc)/(lamda_(min))=(h)/(sqrt(2meV))eV` or `(lamda)/(lamda_(min))propsqrtV`