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When photons of energy (hc)/(lamda) fall...

When photons of energy `(hc)/(lamda)` fall on a metal surface, photoelectrons are ejected from it. If the work function of the surfacei s `hupsilon_0`, then

A

maximum kinetic energy of the electron is `[((hc)/(lamda))-hv_0]`

B

maximum kinetic energy of the photoelectron is equal to `((hc)/(lamda))`

C

minimum KE of the photoelectron is zero

D

minimum kinetic energy of the photoelectron is equal to `(hc)/(lamda)`

Text Solution

Verified by Experts

The correct Answer is:
A, C
Use Einstein's photoelectric equation.
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