The energy reveived from the sun by the earth and surrounding atmosphere is 2 cal`cm^(-2)` `"min"^(-1)` on a surface normal to the rays of sun.
Q. At what rate, in mega gram per minute, must hydrogen be consumed in fusion reaction to provide the sun with the energy it radiates? (Take mass defect per reaction to be `0.028706` a.m.u)

Options

A. `3.66xx10^(14)` mega gram `min^(-1)`
B. `3.66xx10^(16)` mega gram `min^(-1)`
C. `3.66xx10^(-15)` mega gram `min^(-1)`
D. `3.66xx10^(10)` mega gram `min^(-1)`

Answer

B

Explanation

We know that `4HrarrHe+Q`
(As by fusion of four atoms of `H_2`, one Helium atom is formed and energy is released)
`Q`(in a.m.u.) `=(4xx1.008145)-4.003874`
`=0.028706` a.m.u.
`=0.028706xx931xx1.6xx10^(-19)`
Mass of hydrogen required is
`(4.032580xx1.659xx10^(-24)xx2.33xx10^(28))/(0.028706xx931xx1.6xx10^(-19))`
`=3.6673xx10^(16)` mega gram `min^(-1)`