The de Broglie wavelength of an electron moving with a velocity of `1.5xx10^(8)ms^(-1)` is equal to that of a photon find the ratio of the kinetic energy of the photon to that of the electron.

Explanation

To solve the problem, we need to find the ratio of the kinetic energy of a photon to that of an electron, given that their de Broglie wavelengths are equal.

### Step 1: Understand the de Broglie wavelength
The de Broglie wavelength (\( \lambda \)) of a particle is given by the formula:
\[ \lambda = \frac{h}{p} \]
where \( h \) is Planck's constant and \( p \) is the momentum of the particle. For an electron, the momentum \( p \) can be expressed as:
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