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A pulse of light of duration 100ns is ab...

A pulse of light of duration `100ns` is absorbed completely by a small object initially at rest power of the pulse is `30 mW` and the speed of light is `3 xx 10^(8) ms^(-1)` The final momentum of the object is

A

`0.3xx10^(-17)kgms^(-1)`

B

`1.0xx10^(-17)kgms^(-1)`

C

`0.3xx10^(-17)kgms^(-1)`

D

`9.0xx10^(-17)kgms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`t=100xx10^(-9)`s,`P=30xx10^(-3)`W,`C=Cxx10^(8)ms^(-1)`
Momentum
`=(Pt)/(C)=(30xx10^(-3)xx1000xx10^(-9))/(3xx10^(8))=1.0xx10^(-17)kgms^(-1)`
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