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An alpha particle and a proton are accel...

An `alpha` particle and a proton are accelerated from rest by a potential difference of 100V. After this, their de-Broglie wavelengths are `lambda_a`
and `lambda_p` respectively. The ratio `(lambda_p)/(lambda_a)`, to the nearest integer, is.

Text Solution

Verified by Experts

`(1)/(2)mv^2=qV`
`lamda=(h)/(mv)`
`lamda=sqrt8=3`
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Knowledge Check

  • An alpha particle and a proton are accelerated from rest by a potential difference of 200 V. After this, their de Broglie wavelengths are lambda_(alpha) and lambda_(p) respectively. The ratio (lambda_(p))/(lambda_(alpha)) is :

    A
    `3.8`
    B
    8
    C
    `7.8`
    D
    `2.8`

  • de-Broglie wavelength lambda is

    A
    proportional to mass
    B
    proportional to impulse
    C
    inversely proportional to impulse
    D
    independent to impulse

  • The de Broglie wavelength lambda of a particle

    A
    is proportional to mass
    B
    is proportional to impluse
    C
    is inversely proportional to impulse
    D
    does not depend on impulse

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    An alpha -particle and a proton are accelerated from rest through the same potential difference V. Find the ratio of de-Broglie wavelength associated with them.

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    The de Broglie wavelength lambda of a particle

    Choose the most appropriate option. Electrons are accelerated through a potential difference V_(o) and protons are accelerated through a potential difference of 4 V. The de-Broglie wavelengths are lambda_(e ) and lambda_(p) for electrons and protons, respectively. The ratio of (lambda_(e ))/(lambda_(p)) is given by (given, me is mass of electrons and m_(p) is mass of proton)

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