The orbiting `v_(n) of e^(bar)` in the nth orbit in the case of positronium is x-field compared to that in the nth orbit in a hydrogen atom , where `x` has the value

Options

A. 1
B. `sqrt2`
C. `1// sqrt2`
D. 2

Answer

A

Explanation

`m v_(0)^(2) = K//r_(n)`. Since modified `m` is half and modified `r_(n)` is double, `v_(n)` remain the same as in `H`- atom.