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Consider a spectral line resulting n = 5...

Consider a spectral line resulting `n = 5` to `n = 1`, in the atom and loss given below. The shortest wavelength is produced by

A

helium atom

B

deuterium atom

C

singly ionization helium

D

ten times ionized sodium atom

Text Solution

Verified by Experts

The correct Answer is:
D
`(1)/(lambda) = Z^(2) R ((1)/(1^(2)) - (1)/(5^(2)))`
Hence `lambda` is minimum when `Z` is maximum.
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