if the electron in hydrogen orbit jumps form third orbit to second orbit, the wavelength of the emitted radiation is given by

Options

A. `lambda = ( R)/(6)`
B. `lambda = (36)/(5 R)`
C. `lambda = ( 6)/(R)`
D. `lambda = (5 R)/(36)`

Answer

B

Explanation

`(1)/(lambda) = R [(1)/(2^(2)) - (1)/(3^(2))] = (5 R)/(36) : lambda = (36)/(5 R)`