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The wavelength of the first line of Lyma...

The wavelength of the first line of Lyman series in hydrogen atom is `1216`. The wavelength of the first line of Lyman series for `10` times ionized sodium atom will be added

A

`0.1 Å`

B

`1000 Å`

C

`100 Å`

D

`10 Å`

Text Solution

Verified by Experts

The correct Answer is:
D
`lambda prop (1)/(Z^(2))`
Now, `lambda_(Na) = (1216)/(11 xx 11) = 10 Å`
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