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With the increase in peinciple quantum n...

With the increase in peinciple quantum number, the energy difference between the two successive energy levels

A

decrease

B

increase

C

first decrease and then increase

D

remain the same

Text Solution

Verified by Experts

The correct Answer is:
A

Total energy for nth level `= - (13.6)/(n^(2)) eV`
`E_(2) - E_(1) = - 13.6 ((1)/(4) - (1)/(1))`
`= (13.6 xx 3)/(4) = 0.75 xx 13.6 eV`
`E_(3) - E_(2) = - 13.6 ((1)/(9) - (1)/(4))`
`= (13.6 xx 5)/(36) = 0.14 xx 13.6 eV`
`E_(4) - E_(3) = - 13.6 ((1)/(16) - (1)/(9))`
`= (13.6 xx 7)/(144) eV = 0.05 xx 13.6 eV`
Obvionusly, the different of energy between consecutive energy levels decrease.
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