The orbital velocity of electron in the ground state is `v`. If the electron is excited to enegry staet `- 0.54 eV` its orbital velocity will be

Options

A. `v`
B. `(v)/(3)`
C. `(v)/(5)`
D. `(v)/(7)`

Answer

C

Explanation

`E_(n) = - (13.6)/(n^(2)) implies n^(2) = - (13.6)/(-0.54)`
or `n^(2) = 25.2 or n = 5` (nearly)
`As v prop 1//n , so v_(n) = (v)/(5)`