How many time does the electron go round the first bohr orbit of hydrogen atoms in `1 s`?

Options

A. `6.62 xx 10^(15)`
B. 100
C. 1000
D. 1

Answer

A

Explanation

Frequency of electron revolution:
`f = (m Z^(2) e^(4))/(4 epsilon_(0)^(2) n^(3) h^(3))`
Put the various value to get
`f = 6.62 xx 10^(15) (Z^(2))/(n^(3))`
Now put `Z = 1 and n = 1` to get
`f = 6.62 xx 10^(15) H z`