The shortest wavelength of the Brackett series of a hydrogen-like atom (atomic number of `Z` ) is the same as the shortest wavelength of the Balmer series of hydrogen atom. The value of `z` is

Options

A. 4
B. 2
C. 3
D. 6

Answer

B

Explanation

`R [(1)/(1^(2)) - (1)/(oo^(2))] = R Z^(2) [(1)/(2^(2)) - (1)/(oo^(2))] or Z = 2`