The power of an X-ray tube is `16 W`. If the potential difference applied across the tube is `51 kV` , then the number of electrons striking the target per second is

Options

A. `8.4 xx 10^(16)`
B. `5 xx 10^(17)`
C. `2 xx 10^(16)`
D. `2 xx 10^(19)`

Answer

C

Explanation

Let `n` be the number of electron per second stricking the target .
`P = V 1`
`16 W = (5 xx 10^(3)V) xx ne`
`:. N = (16)/(5 xx 10^(3) xx 1.6 xx 10^(-10)) = 2 xx 10^(16)`