The potential different across the Coolidge tube is `20 kV and 10 m A` current flows through the voltage supply. Only `0.5%` of the energy carried by the electrons striking the largest is converted into X-ray. The power carried by the X-ray beam is `p`. Then

Options

A. `P = 0.1 W`
B. `P = 1 W`
C. `P = 2 W`
D. `P = 10 W`

Answer

B

Explanation

`P = VI`
Therefore, total power down by Coolidge tube `P_(T) = VI = 200 W`.
As `0.5 %` of the energy is corried by X-ray is
`0.5 % of P_(T) = (0.5)/(100) xx 200 = 1 W`