An electron in the ground state of hydrogen has an angular momentum `L_(1)` and an electron in the fist excited state of lithium has an angular momentum `L_(2)`. Then,

Options

A. `L_(1) = L_(2)`
B. `L_(1) = 4 L_(2)`
C. `L_(1) =2 L_(2)`
D. `L_(1) = 2 L_(2)`

Answer

C

Explanation

`L_(1) = (1) (h)/(2 pi)` (i)
(Using Bohr's Quantization Rule)
In the first excited state of Li.
`L_(2) = (2) (h)/(2 pi)` (ii)
`:. (L_(2))/(L_(1)) = 2`