An electtron and a photon have same wavelength . If `p` is the moment of electron and `E` the energy of photons, the magnitude of `p//E in S I` unit is

Options

A. `3.0 xx 10^(8)`
B. `3.33 xx 10^(-9)`
C. `9.1 xx 10^(-31)`
D. `6.64 xx 10^(-34)`

Answer

B

Explanation

`lambda = (h)/(p)` (for electron)
or `p = n//h`
and `E = (hc)/(lambda)` (for photon)
`:. (p)/(E) = (1)/( c) = (1)/(3 xx 10^(8)) = 3.33 xx 10^(-9) s m^(-1)`