In X-ray tube , when the accelerating voltage `V` is halved, the difference between the wavelength of `K_(alpha)` line and minimum wavelength of continuous X-ray spectrum

Options

A. remain constant
B. because more than two times
C. because half
D. because less than two times

Answer

D

Explanation

`Delta lambda = lambda_(K_alpha) - lambda_(min)`
Where `V` is haved, `lambda_(min)` becomes two times but `lambda_(K_alpha)` remains the same.
`:. Delta lambda' = lambda_(K_alpha) - 2 lambda_(min)`
`= 2 (Delta lambda) - lambda_(K_alpha)`
`:. Delta lambda' lt 2 (Delta lambda)`