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Let A(0) be the area enclined by the orb...

Let `A_(0)` be the area enclined by the orbit in a hydrogen atom .The graph of in `(A_(0) //A_(1))` against `ln(n)`

A

will pass through origin

B

will be a straight line with slop `4`

C

will be a monotonically increasing nonlinear curve

D

will be a circle

Text Solution

Verified by Experts

The correct Answer is:
A, B
`r_(n) = n^(2) r_(1)`
In `((A_(n))/(A_(1))) = In `((pin_(n^(2)))/(pir_(1)^(2)))`
`In n^(4) = 41n (n)`
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