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The energy levels of a hypotherical one ...

The energy levels of a hypotherical one electron atom are shown in figure

Find the wave number of the photon emitted for the transition `n = 3 to n = 1`

A

`2.23 xx 10^(7) m^(-1)`

B

`1.009 xx 10^(7) m^(-1)`

C

`3.005 xx 10^(6) m^(-1)`

D

`0.432 xx 10^(6) m^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

`lambda = (12400)/(E_(3)^(Z) - E_(1)^(Z)) = (12400)/(12.52) 990 Å `
Wave number `= (1)/(lambda) = (1)/(990 xx 10^(-10) m) = 1.009 xx 10^(7) m^(-1)`
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